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JEE Advanced 2014 Paper 1
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© examsnet.com
Question : 5
Total: 60
A transparent thin film of uniform thickness and refractive index
n
1
=
1.4
is coated on the convex spherical surface of radius R at one end of a long solid glass cylinder of refractive index
n
2
= 1.5, as shown in the figure. Rays of light parallel to the axis of the cylinder traversing through the film from air to glass get focused at distance
f
1
from the film, while rays of light traversing from glass to air get focused at distance
f
2
from the film. Then
|
f
1
|
=
3
R
|
f
1
|
=
2.8
R
|
f
2
|
=
2
R
|
f
2
|
=
1.4
R
Validate
Solution:
For air to glass
1.5
f
1
=
1.4
−
1
R
+
1.5
−
1.4
R
∴
f
1
=
3
R
For glass to air.
1
f
2
=
1.4
−
1.5
−
R
+
1
−
1.4
−
R
∴
f
2
=
2
R
© examsnet.com
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