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JEE Advanced 2014 Paper 2
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© examsnet.com
Question : 50
Total: 60
For
x
∊
(
0
,
π
)
,the equation
s
i
n
x
+
2
s
i
n
2
x
−
s
i
n
3
x
=
3
has
infinitely many solution
three solutions
one solution
no solution
Validate
Solution:
s
i
n
x
+
2
s
i
n
2
x
−
s
i
n
3
x
=
3
s
i
n
x
+
4
s
i
n
x
c
o
s
x
−
3
s
i
n
x
+
4
s
i
n
3
x
=
3
s
i
n
x
[
−
2
+
4
c
o
s
x
+
4
(
1
−
c
o
s
2
x
)
]
=
3
s
i
n
x
[
2
−
(
4
c
o
s
2
x
−
4
c
o
s
x
+
1
)
]
=
3
s
i
n
x
[
3
−
(
2
c
o
s
x
−
1
)
2
]
=
3
⇒
s
i
n
x
=
1
and
2
c
o
s
x
−
1
=
0
⇒
x
=
π
2
and
x
=
π
3
which is not possible at same time
Hence,no solution
© examsnet.com
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