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JEE Advanced 2015 Paper 1
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© examsnet.com
Question : 13
Total: 60
A ring of mass M and radius R is rotating with angular speed ω about a fixed vertical axis is passing through its center O with tow points masses each of mass
M
8
at rest at O.These masses can moves radially outwards along two massless rods fixed on the rings as shown in figure.At some instant the angular speed of the system is
8
9
ω
and one of the masses is at distance of
3
5
R from O.At this instant the distance of the other mass from O is .
2
3
R
1
3
R
3
5
R
4
5
R
Validate
Solution:
Using conversation of angular momentum
m
R
2
ω
=
(
m
R
2
×
8
9
ω
)
+
(
m
8
×
9
R
2
25
×
8
ω
9
)
+
(
m
8
×
x
2
×
8
ω
9
)
⇒
x
=
4
R
5
© examsnet.com
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