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JEE Advanced 2015 Paper 1
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© examsnet.com
Question : 28
Total: 60
All the energy released from the reaction
X
→
Y
.
△
r
G
0
=
−
193
k
J
m
o
l
−
1
is used for oxidizing
M
+
as
M
+
→
M
3
+
+
2
e
−
,
E
0
=
0.25
V
Under standard condition,the number of moles of
M
+
oxidized when one mole of
X
is converted to
Y
is
[F=96500 C
m
o
l
−
1
]
3 moles
4 moles
5 moles
8 moles
Validate
Solution:
X
→
Y
△
r
G
0
=
−
193
KJ/mol
M
+
→
M
3
+
+
2
e
−
,
E
0
=
0.25
V
△
G
0
for this reaction is
△
G
0
=
−
n
F
E
0
=
−
2
×
(
−
0.25
)
×
96500
=
48250
J/mol
48.25 kJ/mole
So the number of moles of
M
+
oxidized using
X
→
Y
will be
=
193
48.25
=
4
m
o
l
e
s
© examsnet.com
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