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JEE Advanced 2015 Paper 2

PARAGRAPH 1

Light guidance in an optical fiber can be understood by considering a structure comprising of thin solid glasscylinder of refractive index n1 surrounded by a medium of lower refractive index n2. The light guidance in thestructure takes place due to successive total internal reflections at the interface of the media n1 and n2 as shown inthe figure. All rays with the angle of incidence i less than a particular value im are confined in the medium ofrefractive index n1. The numerical aperture (NA) of the structure is defined as sin im.

Question : 17

Total: 60

For two structure namely S1‌with‌n1=

and taking refractive index of water to be 4.3 and that of air to be 1,the correct option(s) is (are)

NA of S1 immersed in water is the same as that of S2 immersed in a liquid of refractive index
16
3√15
NA of S1 immersed in liquid of refaractive index
6
√15
is the same as that of S2 immersed in water
NA of S1 placed is the same as that of S2 immersed in liquid of refractiv index
4
√15
NA of S1 placed in air is the same as that of S2 placed in water

Validate

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