Test Index

JEE Advanced 2015 Paper 2

PARAGRAPH 2

In a thin rectangular metallic strip a constant current I flows along the positive x-direction, as shown in the figure. The length, width and thickness of the strip are l , w and d, respectively. A uniform magnetic field

→

is applied on the strip along the positive y-direction. Due to this, the charge carriers experience a net deflection along the z-direction.This results in accumulation of charge carriers on the surface PQRS and appearance of equal and opposite charges on the face opposite to PQRS. A potential difference along the z-direction is thus developed. Charge accumulation continues until the magnetic force is balanced by the electric force. The current is assumed to be uniformly distributed on the cross section of the strip and carried by electrons.

Question : 19

Total: 60

Consider two different metallic strips(1 and 2) of the same material.Their lenghts are the same ,widths are w1‌and‌w2 and thickness are d1‌and‌d2 respectively.Two points K and M re symmetrically located on the opposite faces parallel to the x-y plane(see figure) V1‌and‌V2are the potential difference between K and M in strips 1 and 2,respectively,Then for a given current through them in a given magnetic field strength B,the correct statement(s) is (are )

If w1=w2‌and‌d1=2d2,‌then‌V2=2V1
If w1=w2‌and‌d1=2d2,‌then‌V2=V1
If w1=2w2‌and‌d1=d2,‌then‌V2=2V1
If w1=2w2‌and‌d1=d2,‌then‌V2=V1

Validate

Go to Question:

Prev Question

Next Question