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JEE Advanced 2015 Paper 2
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© examsnet.com
Question : 56
Total: 60
Let
f
(
x
)
=
7
t
a
n
8
x
+
7
t
a
n
6
x
−
3
t
a
n
4
x
−
3
t
a
n
2
x
for all
x
∊
(
−
π
2
,
π
2
)
.Then the correct expression(s) is (are)
π
4
∫
0
x
f
(
x
)
=
1
12
π
4
∫
0
f
(
x
)
d
x
=
0
π
4
∫
0
x
f
(
x
)
d
x
=
1
6
π
4
∫
0
f
(
x
)
d
x
=
1
Validate
Solution:
f
(
x
)
=
(
7
t
a
n
6
x
−
3
t
a
n
2
x
)
(
t
a
n
2
x
+
1
)
π
4
∫
0
f
(
x
)
d
x
=
π
4
∫
0
(
7
t
a
n
6
x
−
3
t
a
n
2
x
)
s
e
c
2
x
d
x
⇒
π
4
∫
0
f
(
x
)
d
x
=
0
π
4
∫
0
x
f
(
x
)
d
x
=
[
x
∫
f
(
x
)
d
x
]
0
π
4
−
π
4
∫
0
[
∫
f
(
x
)
d
x
]
d
x
π
4
∫
0
x
f
(
x
)
d
x
=
1
12
© examsnet.com
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