f(x)=[x2]−3 g(x)=(|x|+|4x−7|)([x2]−3) ∵f is discontinuous at x=1,√2,√3,2 in [−
1
2
,2] and |x|+|4x−7|≠0 at x=1,√2,√3,2 ⇒g(x) is discontinuous at x=1,√2,√3,2 In (0−δ,0+δ) g(x)=(|x|+|4x−7|).(−3) ⇒'g' is non derivable at x=0. In