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JEE Advanced 2017 Paper 1

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Column 1, 2 and 3 contains conics, equations of tangents to the conics and points of contact, respectively.
Column 1Column 2Column 3
(I) x2+y2=a2x^2+y^2=a^2(i) my=m2x+amy=m^2x+a(Q)(am2,2am)(Q) \left(\frac{a}{m^{2}},\frac{2a}{m}\right)
(II) x2+a2y2=a2x^{2}+a^{2}y^{2}=a^{2}(ii) y=mx+am2+1y=mx+a\sqrt{m^{2}+1}(Q) (−mam2+1,am2+1)\left(\frac{-ma}{\sqrt{m^{2}+1}},\frac{a}{\sqrt{m^{2}+1}}\right)
(III) y2=4axy^{2}=4ax(iii) y=mx+a2m2−1y=mx+\sqrt{a^{2}m^{2}-1}(R) (−a2ma2m2+1,1a2m2+1)\left(\frac{-a^{2}m}{\sqrt{a^{2}m^{2}+1}},\frac{1}{\sqrt{a^{2}m^{2}+1}}\right)
(IV) x2−a2y2=a2x^{2}-a^{2}y^{2}=a^{2}(iv) y=mx+a2m2+1y=mx+\sqrt{a^{2}m^{2}+1}(S) (−a2ma2m2−1,−1a2m2−1)\left(\frac{-a^{2}m}{\sqrt{a^{2}m^{2}-1}},\frac{-1}{\sqrt{a^{2}m^{2}-1}}\right)
Section: Mathematics
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