at time t is θ=ωt |ϕ1|=BAcosωt⇒|ε1|=BAωsin(ωt) |ϕ2|=2BAcos(ωt)⇒|ε2|=2BAωsin(ωt) Due to orientation of loops, the two EMFs will work against each other. So, ε(net)|=BAωsin(ωt) So, (A) is correct . We can see that εnet is maximum when θ=
π
2
.So,(B) is correct.Obviously,(C) is incorrect.(D) is incorrect as the EMF is proportional to difference in areas.