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JEE Advanced 2017 Paper 1
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© examsnet.com
Question : 9
Total: 54
A monochromatic light is traveling in a medium of refractive index
n
=
1.6
. It enters a stack of glass layers from the bottom side at an angle
θ
=
30
°
. The interfaces of the glass layers are parallel to each other. The refractive indices of different glass layers are monotonically decreasing as
n
m
=
n
−
m
Δ
n
, where
n
m
is the refractive index of the mth slab and
Δ
n
=
0.1
(see the figure). The ray is refracted out parallel to the interface between the
(
m
−
1
)
t
h
and mth slabs from the right side of the stack. what is the value of m?
Your Answer:
Validate
Solution:
We know that for the given case,
μ
s
i
n
θ
=
constant
So,
1.6
s
i
n
(
30
°
)
=
(
n
−
m
Δ
n
)
s
i
n
90
°
i.e.
0.8
n
−
m
Δ
n
Solving,
m
=
8
© examsnet.com
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