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JEE Advanced 2018 Paper 1
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© examsnet.com
Question : 25
Total: 54
Among the species given below, the total number of diamagnetic species is ________ .H atom,
N
O
2
monomer,
O
2
−
(superoxide), dimeric sulphur in vapour phase,
M
n
3
O
4
,
(
N
H
4
)
2
[
F
e
C
l
4
]
,
(
N
H
4
)
2
[
N
i
C
l
4
]
,
K
2
M
n
O
4
,
K
2
C
r
O
4
Your Answer:
Validate
Solution:
* H-atom=
1
S
1
Parmagnetiic
*
N
O
2
=
Paramagnetic
*
O
2
−
(superoxide) = One unpaired electrons in
π
*
M.O
Paramagnetic
*
S
2
(in vapour phase) = same as
O
2
,two unpaired
e
−
s are present in
π
*
M.O
Paramagnetic
*
M
n
3
O
4
=
2
+
2
M
n
O
.
M
+
4
n
O
2
Paramagnetic
*
(
N
H
4
)
2
[
F
e
C
l
4
]
=
F
e
+
2
=
3
d
6
4
s
0
Paramagnetic
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