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JEE Advanced 2018 Paper 1
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© examsnet.com
Question : 49
Total: 54
Let a, b, c be three non-zero real numbers such that the equation
√
3
a
c
o
s
x
+
2
b
s
i
n
x
=
c
,
x
∊
[
−
π
2
,
π
2
]
has two distinct real roots
α
and
β
with
α
+
β
=
π
3
.Then the value of
b
a
is.....
Your Answer:
Validate
Solution:
√
3
c
o
s
x
+
2
b
a
s
i
n
x
=
c
a
Now,
√
3
c
o
s
α
+
2
b
a
s
i
n
α
=
c
a
.............(1)
√
3
c
o
s
β
+
2
b
a
s
i
n
β
=
c
a
.....(2)
√
3
[
c
o
s
α
−
c
o
s
β
]
+
2
b
a
(
s
i
n
α
−
s
i
n
β
)
=
0
√
3
[
−
2
s
i
n
(
α
+
β
2
)
s
i
n
(
α
−
β
2
)
]
+
2
b
a
[
2
c
o
s
(
α
+
β
2
)
s
i
n
(
α
+
β
2
)
]
=
0
−
√
3
+
2
√
3.
b
a
=
0
b
a
=
1
2
=
0.5
© examsnet.com
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