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JEE Advanced 2018 Paper 2
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© examsnet.com
Question : 27
Total: 54
To measure the quantity of
M
n
C
l
2
dissolved in an aqueous solution, it was completely converted to
K
M
n
O
4
using the reaction
M
n
C
l
2
+
K
2
S
2
O
8
+
H
2
O
→
K
M
n
O
4
+
H
2
S
O
4
+
H
C
l
(equation not balanced).Few drops of concentrated HCl were added to this solution and gently warmed. Further, oxalic acid(225 g) was added in portions till the colour of the permanganate ion disappeard. The quantity of
M
n
C
l
2
(in mg) present in the initial solution is _____.
(Atomic weights in g
m
o
l
−
1
:
M
n
=
55
,
C
l
=
35.5
)
Your Answer:
Validate
Solution:
M
n
C
l
2
amol
+
K
2
S
2
O
8
+
H
2
O
→
K
M
n
O
4
amole
+
H
2
S
O
4
+
H
C
l
C
2
O
4
−
+
M
n
O
4
−
H
+
–
–
–
–
>
C
O
2
m
eq
o
f
C
2
O
4
−
=
m
eq
o
f
M
n
O
4
−
2
×
0.225
/
90
=
a
×
5
a
=
1
×
[
55
+
71
]
=
126
m
g
© examsnet.com
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