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JEE Advanced 2019 Paper 1

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Question : 46

Total: 54

Let B denote a curve y=y(x) which is in the first quadrant and let the point (1,0) lie on it. Let the tangent to B at a point P intersect the y - axis at YP.if PYP has length 1 for each point P on B, then which of the following options is/are correct?

y=−loge(‌‌
1+√1−x2
x
)+√1−x2
y=loge(‌‌
1+√1−x2
x
)−√1−x2
xy′+√1−x2=0
xy′−√1−x2=0

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