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JEE Advanced 2020 Concept Recapitulation Test 3 Paper 1

Answer questions 47,48 and 49 by appropriately matching the information given in the three columns of the following table.

Column - 1

Column - 2

Column - 3

(I) Minimum value of ‌

[|z|2+|z−3|2+|z−6i|2]

(i) M=1

(P) |z−2−3i|2+|z−4−3i|2=M represent the equation of circle with least radius

(II) If |z−2−2|≤1. Then minimum value of ‌

|2iz+4|=M

(ii) M=4

(Q)|z−2−3i|+|z+2+i|=M represent an ellipse

(III) |z+2−i|=5 Maximum value of ‌

|3z+9−7|∣=M

(iii) M=10

(R) ‌

|z−z1|

|z−z2|

=M represent equation of bisector

(IV) |z−‌

|=2 Maximum value of [|z|]=M (where [.] denotes the greatest integer function)

(iv) M=3

(S) ω(1+ω)M+ω2(ω+ω2)M+(−1)M=0 is cube root unity

Question : 47

Total: 54

Which of the following option is the only CORRECT combination?

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