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JEE Advanced 2020 Paper 2

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Each question has FOUR options. ONE OR MORE THAN ONE of these four option(s) is(are) correctanswer(s).

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Question : 9

Total: 54

A rod of mass m and length L, pivoted at one of its ends, is hanging vertically. A bullet of the same mass moving at speed v strikes the rod horizontally at a distance x from its pivoted end and gets embedded in it. The combined system now rotates with angular speed ω about the pivot. The maximum angular speed ωM is achieved for x=xM. Then

ω=
3vx
L2+3x2
ω=
12vx
L2+12x2
xM=
L
√3
ωM=
v
2L
√3

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