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JEE Advanced 2021 Paper 2

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Reaction of

x {g}

{Sn}

with

{HCl}

quantitatively produced a salt. Entire amount of the salt reacted with

y

g of nitrobenzene in the presence of required amount of

{HCl}

to produce

1.29 {g}

of an organic salt (quantitatively).

(Use Molar masses (in g

{mol}^{-1}

) of

{H}, {C}, {N}, {O}, {Cl}

and

{Sn}

as 1,12 ,

14,16,35

and 119 , respectively).

Section: Chemistry

Question : 28 of 57

Marks: +1, -0

The value of

x

Solution:

The value of

x

So to get

1.29\ \mathrm{g}

organic salt.

We have to form

0.01

mole salt.

0.01

mole nitrobenzene is required

0.03

mole

\mathrm{Sn}

is required.

So the amount of nitrobenzene

=0.01 \times 123=1.23\ \mathrm{g}

the amount of Sn required

=0.01 \times 357=3.57\ \mathrm{g}

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