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JEE Advanced 2022 Paper 1
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© examsnet.com
Question : 51
Total: 54
Match the rate expressions in LIST-I for the decomposition of X with the corresponding profiles
provided in LIST-II. Xs and k constants having appropriate units.
List - I
List - II
(I)
rate
=
k
[
X
]
X
s
+
[
X
]
under all possible initial concentration of X
(P)
(II)
rate
=
k
[
X
]
X
s
+
[
X
]
where initial concentration of
X
are much less than
X
s
(Q)
(III)
rate
=
k
[
X
]
X
s
+
[
X
]
where initial concentration of
X
are much higher than
X
s
(R)
(IV)
rate
=
k
[
X
]
2
X
s
+
[
X
]
where initial concentration of
X
is
much higher than
X
s
(S)
(T)
I
→
P
;
II
→
Q
;
III
→
S
;
IV
→
T
I
→
R
;
II
→
S
;
III
→
S
;
IV
→
T
I
→
P
;
II
→
Q
;
III
→
Q
;
IV
→
R
I
→
R
;
II
→
S
;
III
→
Q
;
IV
→
R
Validate
Solution:
(I) rate
=
k
[
x
]
x
s
+
[
x
]
=
k
x
s
[
x
]
+
1
If
[
x
]
→
∞
⇒
rate
→
k
⇒
order
=
0
⇒
(
I
)
−
(
R
)
,
(
P
)
(II)
[
x
]
<
<
x
s
⇒
rate
=
k
[
x
]
x
s
⇒
order
=
1
⇒
(
II
)
−
(
Q
)
,
(
T
)
(III)
[
x
]
>
>
x
s
⇒
rate
=
k
⇒
order
=
0
⇒
(
III
)
−
(
P
)
,
(
S
)
(IV) rate
=
k
[
x
]
2
x
s
+
[
x
]
[
x
]
>
>
x
s
⇒
rate
=
k
[
x
]
⇒
(
IV
)
−
(
Q
)
,
(
T
)
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