When light of a given wavelength is incident on a metallic surface, the minimum potential needed to stop the emitted photoelectrons is 6.0V. This potential drops to 0.6V if another source with wavelength four times that of the first one and intensity half of the first one is used. What are the wavelength of the first source and the work function of the metal, respectively? [Take ‌
hc
e
=1.24×10−6JmC−1.]
[JEE Adv 2022 P2]

Question

hc

e

=1.24×10−6JmC−1.]

[JEE Adv 2022 P2]

Accepted Answer

Correct Answer is : 1.72×10−7m,1.20‌eV

Answer

1.72×10−7m,1.20‌eV

Answer

1.72×10−7m,5.60‌eV

Answer

3.78×10−7m,5.60‌eV

Answer

3.78×10−7m,1.20‌eV

JEE Advanced 2022 Paper 2