A thin conducting rod MN of mass 20\ {gm}, length 25\ {cm} and resistance 10\ is held on frictionless, long, perfectly conducting vertical rails as shown in the figure. There is a uniform magnetic field B₀=4\ {T} directed perpendicular to the plane of the rod-rail arrangement. The rod is released from rest at time t=0 and it moves down along the rails. Assume air drag is negligible. Match each quantity in List-I with an appropriate value from List-II, and choose the correct option. [Given: The acceleration due to gravity g=10\ {m}\ {s}^{-2} and e^{-1}=0.4 ] List-I List-II (P) At t=0.2\ {s}, the magnitude of the induced emf in Volt (1) 0.07 (Q) At t=0.2\ {s}, the magnitude of the magnetic force in Newton (2) 0.14 (R) At t=0.2\ {s}, the power dissipated as heat in Watt (3) 1.20 (S) The magnitude of terminal velocity of the rod in {m}\ {s}^{-1} (4) 0.12 (5) 2.00 [JEE Adv 2023 P1]

Question

Examsnet · Accepted Answer

Correct Answer is : P→3, Q→4, R→2, S→5P arrow 3,\ Q arrow 4,\ R arrow 2,\ S arrow 5P→3, Q→4, R→2, S→5

List-I	List-II
(P) At $t=0.2\ \mathrm{s}$ , the magnitude of the induced emf in Volt	(1) 0.07
(Q) At $t=0.2\ \mathrm{s}$ , the magnitude of the magnetic force in Newton	(2) 0.14
(R) At $t=0.2\ \mathrm{s}$ , the power dissipated as heat in Watt	(3) 1.20
(S) The magnitude of terminal velocity of the rod in $\mathrm{m}\ \mathrm{s}^{-1}$	(4) 0.12
	(5) 2.00

JEE Advanced 2023 Paper 1 Solutions