From the question Af=1015,Ab=1011‌, ‌ f= Forward reaction log‌K at 500K=6  b= Backward reaction log‌kf at 500K=9 (from graph) log‌kb at 500K : log‌K=log(‌
kf
kb
)‌‌‌ since ‌⇒K=‌
kf
kb
6=log‌kf−log‌kb 6=9−log‌kb log‌kb=3‌ at ‌500K log‌