H0 will be the plane containing the line ℓ1 and parallel to ℓ2. ∴ Normal vector of plane parallel ℓ1 and ℓ2 is
i^11j^10k^11=j^(1)−j^(1−1)+k^(−1)=i^−k^
∴H0:x−z=c∣(0,0,0)⇒C=0∴H0:x−z=0 (P) d(H0)=1 distance of point (0,1,−1) from H.d=20−(−1)=21∴P→5(Q) d=20−2=2∴Q→4(R) d=20=0∴R→3(S) Point of intersection will be (1,1,1)∴S→1d=1+1+1=3∴ Option (B) is correct.