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JEE Advanced 2023 Paper 2 Solutions
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© examsnet.com
Question : 25
Total: 52
H
2
S
(5 moles) reacts completely with acidified aqueous potassium permanganate solution. In this reaction, the number of moles of water produced is
x
, and the number of moles of electrons involved is
y
. The value of
(
x
+
y
)
is ________
Your Answer:
Validate
Solution:
KMnO
4
H
+
→
Mn
+
2
S
−
2
→
0
S
∴
n
factor
of
KMnO
4
=
5
n
factor of
S
−
2
(
H
2
S
)
=
2
(
n
KMnO
4
×
5
)
=
(
5
×
2
)
H
2
S
[
(
GEN
)
KMnO
4
=
(
GEP
)
H
2
S
]
∴
n
KMnO
4
=
2
∴
2
KMnO
4
+
3
H
2
SO
4
+
5
H
2
S
→
K
2
SO
4
+
2
MnSO
4
+
5
S
+
8
H
2
O
Number of moles of water produced
=
′
8
′
Number of moles of electrons involved
=
10
∴
x
=
8
,
y
=
10
⇒
(
x
+
y
)
=
18
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