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JEE Advanced 2024 Paper 2
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© examsnet.com
Question : 6
Total: 51
A table tennis ball has radius
(
3
∕
2
)
×
10
−
2
m
and mass
(
22
∕
7
)
×
10
−
3
‌
kg
. It is slowly pushed down into a swimming pool to a depth of
d
=
0.7
m
below the water surface and then released from rest. It emerges from the water surface at speed
v
, without getting wet, and rises up to a height
H
. Which of the following option(s) is (are) correct?
[Given:
Ï€
=
22
∕
7
,
g
=
10
ms
−
2
, density of water
=
1
×
10
3
‌
kg
‌
m
−
3
, viscosity of water
=
1
×
10
−
3
‌
Pa
−
s
.]
[JEE Adv 2024 P2]
The work done in pushing the ball to the depth d is 0.077 J .
If we neglect the viscous force in water, then the speed
v
=
7
m
∕
s
.
If we neglect the viscous force in water, then the height
H
=
1.4
m
.
The ratio of the magnitudes of the net force excluding the viscous force to the maximum viscous force in water is 500/9.
Validate
Solution:
© examsnet.com
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