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JEE Advanced 2025 Paper 1

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Question : 14

Total: 48

Consider the following frequency distribution:

Value	4	5	8	9	6	12	11
Frequency	5	f1	f2	2	1	1	3

Suppose that the sum of the frequencies is 19 and the median of this frequency distribution is 6.
For the given frequency distribution, let α denote the mean deviation about the mean, β denote the mean deviation a the median, and σ2 denote the variance.
Match each entry in List-I to the correct entry in List-II and choose the correct option.

	List-I		List-II
(P)	7f1+9f2 is equal to	(1)	146
(Q)	19α is equal to	(2)	47
(R)	19β is equal to	(3)	48
(S)	19α2 is equal to	(4)	145
		(5)	55

[JEE Adv 2025 P1]

(P) ⟶ (5) (Q) ⟶ (3) (R) ⟶ (2) (S) ⟶ (4)
(P) ⟶ (5) (Q) ⟶ (2) (R) ⟶ (3) (S) ⟶ (1)
(P) ⟶ (5) (Q) ⟶ (3) (R) ⟶ (2) (S) ⟶ (1)
(P) ⟶ (3) (Q) ⟶ (2) (R) ⟶ (5) (S) ⟶ (4)

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