Consider the following frequency distribution: Value 4 5 8 9 6 12 11 Frequency 5 f₁ f₂ 2 1 1 3 Suppose that the sum of the frequencies is 19 and the median of this frequency distribution is 6. For the given frequency distribution, let α denote the mean deviation about the mean, β denote the mean deviation a the median, and ² denote the variance. Match each entry in List-I to the correct entry in List-II and choose the correct option. List-I List-II (P) 7 f₁+9 f₂ is equal to (1) 146 (Q) 19 α is equal to (2) 47 (R) 19 β is equal to (3) 48 (S) 19 α² is equal to (4) 145 (5) 55 [JEE Adv 2025 P1]

Question

Examsnet · Accepted Answer

Correct Answer is : (P) ⟶⟶ (5) (Q) ⟶⟶ (3) (R) ⟶⟶ (2) (S) ⟶⟶ (1)

Value (xi)	$f_i$	cf	$f_i x_i$
4	5	5	20
5	$f_1$	$5+f_1$	20
6	1	$6+f_1$	6
8	$f_2$	$6+f_1+f_2$	24
9	2	$8+f_1+f_2$	18
11	3	$11+f_1+f_2$	33
12	1	$12+f_1+f_2$	12

	List-I		List-II
(P)	$7 f_1+9 f_2$ is equal to	(1)	146
(Q)	$19 \alpha$ is equal to	(2)	47
(R)	$19 \beta$ is equal to	(3)	48
(S)	$19 \alpha^2$ is equal to	(4)	145
		(5)	55

JEE Advanced 2025 Paper 1