Let {w}={i}+{j}-2{k}, and {u} and {v} be two vectors, such that {u}×{v}={w} and {v}×{w}={u}. Let α, β, , and t be real numbers such that {u}=α{i}+β{j}+{k}, -tα+β+=0, α-tβ+=0, \;{ and }\; α+β-t=0 Match each entry in List-I to the correct entry in List-II and choose the correct option. List-I List-II (P) |{v}|² is equal to (1) 0 (Q) If α={3}, then ² is equal to (2) 1 (R) If α={3}, then (β+)² is equal to (3) 2 (S) If α={2}, then t+3 is equal to (4) 3 (5) 5 [JEE Adv 2025 P1]

Question

Examsnet · Accepted Answer

Correct Answer is : (P) →arrow→ (2) (Q) →arrow→ (1) (R) →arrow→ (4) (S) →arrow→ (5)

	List-I		List-II
(P)	$\|\vec{v}\|^2$ is equal to	(1)	0
(Q)	If $\alpha=\sqrt{3}$ , then $\gamma^2$ is equal to	(2)	1
(R)	If $\alpha=\sqrt{3}$ , then $(\beta+\gamma)^2$ is equal to	(3)	2
(S)	If $\alpha=\sqrt{2}$ , then $t+3$ is equal to	(4)	3
		(5)	5

JEE Advanced 2025 Paper 1