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JEE Advanced 2026 Paper 2

Section: Mathematics

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Question : 9 of 54

Marks: +1, -0

Ten moles of an ideal monoatomic gas, initially in state

\boldsymbol{a}

at atmospheric pressure and temperature

T_a=27^{\circ} \mathrm{C}

, is enclosed in a metal cylinder of volume

V_0

fitted with a frictionless piston. The gas is suddenly compressed to state

\boldsymbol{b}

V_0 / 3

. Now, keeping the piston stationary, the cylinder is submerged in a water bath of temperature

11^{\circ} \mathrm{C}

until the gas reaches the temperature of the water bath, which is denoted as state

\boldsymbol{c}

. Finally, while still in the water bath, the piston is brought slowly to its initial position, which is denoted as state

\boldsymbol{f}

R

is universal gas constant, then the correct option(s) is/are :

9^{1 / 3}=2.08

[JEE Adv 2026 P2]

The schematic P-V diagram of the processes described above is :
The change in internal energy in going from state a to b is $4860R$ .
The net change in the internal energy in the whole process is $-240R$ .
The pressure and temperature of the state b are $2.08$ times the atmospheric pressure and $624\,K$ , respectively.

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