Test Index

p Block Elements

Section: Chemistry

Question : 14 of 62

Marks: +1, -0

Upon heating, $\mathrm{H}_3\mathrm{PO}_3$ undergoes disproportionation reaction to produce $\mathrm{H}_3\mathrm{PO}_4$ and $\mathrm{PH}_3$ .
While $\mathrm{H}_3\mathrm{PO}_3$ can act as reducing agent, $\mathrm{H}_3\mathrm{PO}_4$ cannot.
$\mathrm{H}_3\mathrm{PO}_3$ is a monobasic acid.
The $\mathrm{H}$ atom of $\mathrm{P}-\mathrm{H}$ bond in $\mathrm{H}_3\mathrm{PO}_3$ is not ionizable in water.

Solution:

(a)

4\mathrm{H}_3\mathrm{PO}_3\xrightarrow{\Delta}3\mathrm{H}_3\mathrm{PO}_4+\mathrm{PH}_3

(correct)

(b)

\mathrm{H}_3\mathrm{PO}_4

has "

\mathrm{P}

" in its highest oxidation state, hence cannot act as a reducing agent (correct)

So, it is dibasic acid (incorrect)

(d) The hydrogen which is directly attached to phosphorous does not ionized in water.

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