p Block Elements

Concept:Identify the compounds $P$, $Q$, $R$ from the given reaction sequence and then check their molecular geometry and properties.Explanation:The image shows: $\mathrm{Cl}_2 + \mathrm{F}_2 \to P$; $P + \mathrm{F}_2 \to Q$; $Q + \mathrm{F}_2 \to R$.Thus, $P = \mathrm{ClF}$, $Q = \mathrm{ClF}_3$, $R = \mathrm{ClF}_5$.For $Q$ ($\mathrm{ClF}_3$): Central $\mathrm{Cl}$ has 7 valence electrons, forms 3 bonds, hence has 2 lone pairs. Option A is correct.$\mathrm{ClF}_3$ has a T‑shaped geometry, not perfect octahedral. Option B is incorrect.$\mathrm{ClF}_3$ is a strong fluorinating agent. Option C is correct.For $R$ ($\mathrm{ClF}_5$): Central $\mathrm{Cl}$ forms 5 bonds, has 1 lone pair, giving square pyramidal shape, not trigonal pyramidal. Option D is incorrect.Thus only A and C are correct.Answer:A and C