Test Index

Biomolecules

Section: Chemistry

Question : 9 of 22

Marks: +1, -0

Oxidation of glucose with bromine water gives glutamic acid
Hydrolysis of sucrose gives dextrorotatory glucose and laevorotatory fructose
The two six-membered cyclic hemiacetal forms of D-(+)-glucose are called anomers
Monosaccharides cannot be hydrolysed to give polyhydroxy aldehydes and ketones

Solution:

(1)

\mathrm{Glucose}\xrightarrow[\mathrm{H}_2\mathrm{O}]{\mathrm{Br}_2}\mathrm{Gluconic acid.}

(2)

\mathrm{Sucrose}\xrightarrow[]{{\mathrm{H}_2\mathrm{O}}}\underset{(+)}{\mathrm{Glucose}}+\underset{(-)}{\mathrm{Fructose}}

(3)

(4) Mono saccharioles do not undergoes further hydrolysis is due to absence of etherlinkage.

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