Exams Net
Unrestricted Exams Practice
Home
Exams
Banking
CUET
Defence
Engineering
Finance
GATE
Insurance
International
JEE
LAW
MBA
MCA
Medical
Other
Police
PSC
RRB
SSC
State Govt
Subjectwise
Teacher
SET Exams
UPSC
Aptitude
Algebra and Higher Mathematics
Arithmetic
Commercial Mathematics
Data Based Mathematics
Geometry and Mensuration
Number System and Numeracy
Problem Solving
Board Exams
Andhra
Bihar
CBSE
Gujarat
Haryana
ICSE
Jammu and Kashmir
Karnataka
Kerala
Madhya Pradesh
Maharashtra
Odisha
Tamil Nadu
Telangana
Uttar Pradesh
English
Competitive English
CBSE
CBSE Class 10 Solutions
CBSE Class 12 Solutions
CBSE Question Papers (Pdf)
NCERT Books (Pdf)
NCERT Exemplar Books (Pdf)
NCERT Study Notes (Pdf)
CBSE Study Concepts (Pdf)
NCERT Text Book Class 11 Solutions
NCERT Text Book Class 12 Solutions
ICSE Class 10 Papers
Certifications
Technical
Cloud Tech Certifications
Security Tech Certifications
Management
IT Infrastructure
More
About
Contact Us
Our Apps
Privacy
+
-
Test Index
Isolation of Elements
Show Para
Hide Para
Section:
Chemistry
Share question:
© examsnet.com
Question : 5 of 22
Marks:
+1
,
-0
A mixture of two salts is used to prepare a solution
S
S
S
, which gives the following results :
white precipitate(s) only
→
Dilute NaOH
\text{white precipitate(s) only} \overset{\text{Dilute NaOH}}{\rightarrow}
white precipitate(s) only
→
Dilute NaOH
\longleftarrow
S
Room temperature
  
(
aq. solution of the salts
→
Room temperature
Dilute HCl (aq.)
White precipitate(s) only
)
\underset{\text{Room temperature}}{S} \; ( \text{aq. solution of the salts} \xrightarrow[\text{Room temperature}]{\text{Dilute HCl (aq.)}} \text{White precipitate(s) only} )
Room temperature
S
​
(
aq. solution of the salts
Dilute HCl (aq.)
Room temperature
​
White precipitate(s) only
)
The correct option(s) for the salt mixture is(are)
[JEE Adv 2021 P1]
P
b
(
N
O
3
)
2
\mathrm{Pb}(\mathrm{NO}_3)_2
Pb
(
NO
3
​
)
2
​
and
Z
n
(
N
O
3
)
2
\mathrm{Zn}(\mathrm{NO}_3)_2
Zn
(
NO
3
​
)
2
​
P
b
(
N
O
3
)
2
\mathrm{Pb}(\mathrm{NO}_3)_2
Pb
(
NO
3
​
)
2
​
and
B
i
(
N
O
3
)
3
\mathrm{Bi}(\mathrm{NO}_3)_3
Bi
(
NO
3
​
)
3
​
A
g
N
O
3
\mathrm{AgNO}_3
AgNO
3
​
and
B
i
(
N
O
3
)
3
\mathrm{Bi}(\mathrm{NO}_3)_3
Bi
(
NO
3
​
)
3
​
P
b
(
N
O
3
)
2
\mathrm{Pb}(\mathrm{NO}_3)_2
Pb
(
NO
3
​
)
2
​
and
H
g
(
N
O
3
)
2
\mathrm{Hg}(\mathrm{NO}_3)_2
Hg
(
NO
3
​
)
2
​
Validate
Solution:
P
b
(
N
O
3
)
2
→
 dil.HClÂ
P
b
C
l
 White ppt.
↓
\mathrm{Pb}(\mathrm{NO}_3)_2 \xrightarrow{\text{ dil.HCl }} \mathrm{PbCl}_{\text{ White ppt.}} \downarrow
Pb
(
NO
3
​
)
2
​
 dil.HClÂ
​
PbCl
 White ppt.
​
↓
B
i
(
N
O
3
)
3
→
 dil.HCl
B
i
C
l
3
Water Soluble
\mathrm{Bi}(\mathrm{NO}_3)_3 \xrightarrow{\text{ dil.HCl}} \underset{\text{Water Soluble}}{\mathrm{BiCl}_3}
Bi
(
NO
3
​
)
3
​
 dil.HCl
​
Water Soluble
BiCl
3
​
​
H
g
(
N
O
3
)
2
→
dil.HCl
H
g
C
l
2
Water Soluble
\mathrm{Hg}(\mathrm{NO}_3)_2 \xrightarrow{\text{dil.HCl}} \underset{\text{Water Soluble}}{\mathrm{HgCl}_2}
Hg
(
NO
3
​
)
2
​
dil.HCl
​
Water Soluble
HgCl
2
​
​
A
g
N
O
3
→
dil.HCl
A
g
C
l
White ppt
↓
\mathrm{AgNO}_3 \xrightarrow{\text{dil.HCl}} \underset{\text{White ppt}}{\mathrm{AgCl}} \downarrow
AgNO
3
​
dil.HCl
​
White ppt
AgCl
​
↓
Z
n
(
N
O
3
)
2
→
dil.HCl
Z
n
C
l
2
Water Soluble
\mathrm{Zn}(\mathrm{NO}_3)_2 \xrightarrow{\text{dil.HCl}} \underset{\text{Water Soluble}}{\mathrm{ZnCl}_2}
Zn
(
NO
3
​
)
2
​
dil.HCl
​
Water Soluble
ZnCl
2
​
​
P
b
(
N
O
3
)
2
→
NaOH(dil.)
P
b
(
O
H
)
2
White ppt
↓
\mathrm{Pb}(\mathrm{NO}_3)_2 \xrightarrow{\text{NaOH(dil.)}} \underset{\text{White ppt}}{\mathrm{Pb}(\mathrm{OH})_2} \downarrow
Pb
(
NO
3
​
)
2
​
NaOH(dil.)
​
White ppt
Pb
(
OH
)
2
​
​
↓
Z
n
(
N
O
3
)
2
→
NaOH(dil.)
Z
n
(
O
H
)
2
White ppt.
↓
\mathrm{Zn}(\mathrm{NO}_3)_2 \xrightarrow{\text{NaOH(dil.)}} \underset{\text{White ppt.}}{\mathrm{Zn}(\mathrm{OH})_2} \downarrow
Zn
(
NO
3
​
)
2
​
NaOH(dil.)
​
White ppt.
Zn
(
OH
)
2
​
​
↓
B
i
(
N
O
3
)
2
→
NaOH(dil.)
B
i
(
O
H
)
3
White ppt.
↓
\mathrm{Bi}(\mathrm{NO}_3)_2 \xrightarrow{\text{NaOH(dil.)}} \underset{\text{White ppt.}}{\mathrm{Bi}(\mathrm{OH})_3} \downarrow
Bi
(
NO
3
​
)
2
​
NaOH(dil.)
​
White ppt.
Bi
(
OH
)
3
​
​
↓
A
g
N
O
3
→
NaOH(dil.)
A
g
2
O
Brown ppt
↓
\mathrm{AgNO}_3 \xrightarrow{\text{NaOH(dil.)}} \underset{\text{Brown ppt}}{\mathrm{Ag}_2\mathrm{O}} \downarrow
AgNO
3
​
NaOH(dil.)
​
Brown ppt
Ag
2
​
O
​
↓
H
g
(
N
O
3
)
2
→
NaOH(dil.)
H
g
O
Yellow ppt
↓
\mathrm{Hg}(\mathrm{NO}_3)_2 \xrightarrow{\text{NaOH(dil.)}} \underset{\text{Yellow ppt}}{\mathrm{HgO}} \downarrow
Hg
(
NO
3
​
)
2
​
NaOH(dil.)
​
Yellow ppt
HgO
​
↓
© examsnet.com
Go to Question:
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
Prev Question
Next Question
More Free Exams
AIEEE Previous Papers
BITSAT Exam Previous Papers
JEE Advanced Model Papers
JEE Advanced Previous Papers
JEE Main
JEE Main PYQ
JEE Mains Model Papers
VITEEE Previous Papers