Let \frac{\pi}{2}

Question

Let \frac{\pi}{2}< x< \pi be such that \cot x= {-5}/{\sqrt{11}}. Then ( \sin \frac{11 x}{2}) ( \sin 6 x-\cos 6 x) + (\cos \frac{11 x}{2}) ( \sin 6 x+\cos 6 x) is equal to [JEE Adv 2024 P1]

Examsnet · Accepted Answer

Correct Answer is : ‌√11+12√3

Trigonometric Functions & Equations