Let the functions f: {R} o{R} and {g}: {R} o{R} be defined by f(x)=e^{x-1}-e^{-|x-1|} and g(x)= \frac{1}{2} (e^{x-1}+e^{1-x} ) Then the area of the region in the first quadrant bounded by the curves y=f(x), y=g(x) and x=0 is
[JEE Adv 2020 P1]

Question

Let the functions f: {R}	o{R} and {g}: {R} 	o{R} be defined by f(x)=e^{x-1}-e^{-|x-1|} and g(x)= \frac{1}{2} (e^{x-1}+e^{1-x} ) Then the area of the region in the first quadrant bounded by the curves y=f(x), y=g(x) and x=0 is
[JEE Adv 2020 P1]

Examsnet · Accepted Answer

Correct Answer is : (2−√3)+12(e−e−1)

0,	x<1
ex−1−e−(x−1),	x≥1

Application of Integration