JEE Advanced Model Paper 15 with solutions for online practice

The equation of any plane through (-1,3,2) is a(x + 1) + b(y-3)+c(z-2) = 0..........(i)If this plane (i) is perpendicular to P1 then
2a - b + c = 0 ... (ii)
And if the plane (i) is perpendicular to P2 then
a + 2b - c = 0 ... (iii)
From eq.(ii) and (iii),we get

a

−1

=

b

3

=

c

5

Substituting these proportionate values of a,b,c in eq.(ii),we get the required equation as
— (x + 1)+3(y-3)+5(z-2) = 0Or x —3y —5z + 20 = 0