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JEE Advanced Model Paper 18 with solutions for online practice
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500 ml 0.2M XOH (K b = 10 − 7 ) and 500 ml 0.16 M YOH (K b = 10 − 6 ) are mixedtogether.
Given: log 3 = 0.48
For Questions 33 & 34
500 ml 0.2M XOH (
Given: log 3 = 0.48
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