JEE Advanced Model Paper 3 with solutions for online practice

GD =

1

√2

; AG = √2
Parametric through (0 , 0) ;

x

cosθ

=

y

sinθ

= −√2 (think!)
∴ cos θ =

−1

√2

; sinθ =

−1

√2

; x = -1 ; y = -1
Hence coordinates of D are (

−1

2

,

−1

2

)
Ad = p =

3

√2

, Area of equilateral triangle

=

p2

√3

=

9

2

1

√3

=

3√3

2

Equation ofline through A, y + 1 =1 =m (x + 1) .... (1)As, (1) makes an angle of 60° with BC
∴ |

m+1

1−m

| = √3 ⇒ m = 2 - √3 or 2 + √3