Test Index

Heat and Thermodynamics

Section: Physics

Question : 35 of 73

Marks: +1, -0

Work done in this thermodynamic cycle (1→2→3→4→1) is $|W|=\;\;\frac{1}{2}RT_{0}$
The ratio of heat transfer during processes $1\rightarrow2$ and $2\rightarrow3$ is $\left| \;\;\frac{Q_{1\rightarrow2}}{Q_{2\rightarrow3}} \right|=\;\;\frac{5}{3}$
The ratio of heat transfer during processes 1→2 and 3→4 is $\left| \;\;\frac{Q_{1-2}}{Q_{3,4}} \right|=\;\;\frac{1}{2}$
The above thermodynamic cycle exhibits only isochoric and adiabatic processes.

Solution:

(i) W = Area

=\;\;\left(\frac{nRT_{0}}{2V_{0}}\right)V_{0}

=\frac{1}{2}RT_{0}

(ii)

\;\;\frac{|Q_{12}|}{|Q_{13}|}=\;\;\frac{nC_{p}\Delta T}{nC_{V}\Delta T}=\;\;\frac{5}{3}

(iii)

\left| \;\;\frac{Q_{12}}{Q_{34}} \right|=\;\;\frac{nC_{p}\Delta T_{1}}{nC_{p}\Delta T_{2}}=2

(iv) isochoric and adiabatic

Go to Question:

Prev Question

Next Question