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Motion

Section: Physics

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Question : 10 of 13

Marks: +1, -0

Airplanes A and B are flying with constant velocity in the same vertical plane at angles

30^{\circ}

60^{\circ}

with respect to the horizontal respectively as shown in the figure. The speed of A is

100\sqrt{3}\,\text{m/s}

.At time t =0 s, an observer in A find B at a distance of 500 m. This observer sees B moving with a constant velocity perpendicular to the line of motion of A. If at

t=t_0

,A just escapes being hit by B,

t_0

[JEE Adv 2014 P1]

Your Answer:

Solution:

The relative velocity of b with respect to A is perpendicular to line of motion of A

\therefore V_B

cos

30^{\circ}=V_A

\Rightarrow V_B=200

m/s

and time

t_0

=(Relative distance)/(Relative velocity)

= \frac{500}{V_B \sin 30^{\circ}} = 5

sec

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