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Test Index
Properties of Matter
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Section:
Physics
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Question : 5 of 47
Marks:
+1
,
-0
A bubble has surface tension
S
S
S
. The ideal gas inside the bubble has ratio of specific heats
γ
=
5
3
\gamma=\frac{5}{3}
γ
=
3
5
. The bubble is exposed to the atmosphere and it always retains its spherical shape. When the atmospheric pressure is
P
a
1
P_{a 1}
P
a
1
, the radius of the bubble is found to be
r
1
r_1
r
1
and the temperature of the enclosed gas is
T
1
T_1
T
1
. When the atmospheric pressure is
P
a
2
P_{a 2}
P
a
2
, the radius of the bubble and the temperature of the enclosed gas are
r
2
r_2
r
2
and
T
2
T_2
T
2
, respectively.
Which of the following statement(s) is(are) correct?
[JEE Adv 2022 P2]
If the surface of the bubble is a perfect heat insulator, then
(
r
1
r
2
)
5
=
P
a
2
+
2
S
r
2
P
a
1
+
2
S
r
1
\left(\frac{r_1}{r_2}\right)^5=\frac{P_{a 2}+\frac{2S}{r_2}}{P_{a 1}+\frac{2S}{r_1}}
(
r
2
r
1
)
5
=
P
a
1
+
r
1
2
S
P
a
2
+
r
2
2
S
.
If the surface of the bubble is a perfect heat insulator, then the total internal energy of the bubble
including its surface energy does not change with the external atmospheric pressure.
If the surface of the bubble is a perfect heat conductor and the change in atmospheric temperature is negligible, then
(
r
1
r
2
)
3
=
P
a
2
+
4
S
r
2
P
a
1
+
4
S
r
1
\left(\frac{r_1}{r_2}\right)^3=\frac{P_{a 2}+\frac{4S}{r_2}}{P_{a 1}+\frac{4S}{r_1}}
(
r
2
r
1
)
3
=
P
a
1
+
r
1
4
S
P
a
2
+
r
2
4
S
.
If the surface of the bubble is a perfect heat insulator, then
(
T
2
T
1
)
5
2
=
P
a
2
+
4
S
r
2
P
a
1
+
4
S
r
1
\left(\frac{T_2}{T_1}\right)^{\frac{5}{2}}=\frac{P_{a 2}+\frac{4S}{r_2}}{P_{a 1}+\frac{4S}{r_1}}
(
T
1
T
2
)
2
5
=
P
a
1
+
r
1
4
S
P
a
2
+
r
2
4
S
.
Validate
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