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Units and Measurements
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Section:
Physics
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© examsnet.com
Question : 12 of 36
Marks:
+1
,
-0
A physical quantity
S
‾
\overline{S}
S
is defined as
S
‾
=
E
‾
×
B
‾
μ
0
\overline{S}=\frac{\overline{E} \times \overline{B}}{\mu_{0}}
S
=
μ
0
E
×
B
, where
E
→
\overset{\rightarrow}{E}
E
→
is electric field,
B
‾
\overline{B}
B
is magnetic field and
μ
0
\mu_{0}
μ
0
is the permeability of free space. The dimensions of
S
‾
\overline{S}
S
are the same as the dimensions of which of the following quantities?
[JEE Adv 2021 P2]
Energy
Charge
×
Current
\;\frac{\text{Energy}}{\text{Charge} \times \text{Current}}
Charge
×
Current
Energy
Force
Length
×
Time
\;\frac{\text{Force}}{\text{Length} \times \text{Time}}
Length
×
Time
Force
Energy
Volume
\;\frac{\text{Energy}}{\text{Volume}}
Volume
Energy
Power
Area
\;\frac{\text{Power}}{\text{Area}}
Area
Power
Validate
Solution:
Given physical quantity,
S
→
=
[
E
→
×
B
→
]
1
μ
0
\overset{\rightarrow}{S}=\left[\overset{\rightarrow}{E}\times \overset{\rightarrow}{B}\right] \;\frac{1}{\mu_{0}}
S
→
=
[
E
→
×
B
→
]
μ
0
1
Here
S
S
S
is known as pointing vector and it represents flow of energy per unit area per unit time
S
→
=
Energy
Area
×
Time
=
Power
Area
=
Force
Length
×
Time
\overset{\rightarrow}{S}=\;\frac{\text{Energy}}{\text{Area} \times \text{Time}}\;=\;\frac{\text{Power}}{\text{Area}}\;=\;\frac{\text{Force}}{\text{Length} \times \text{Time}}
S
→
=
Area
×
Time
Energy
=
Area
Power
=
Length
×
Time
Force
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