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Section:
Physics
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© examsnet.com
Question : 4 of 22
Marks:
+1
,
-0
A particle of mass m is initially at rest at the origin. It is subjected to a force and starts moving along the x-axis. Its kinetic energy K changes with time as
d
K
d
t
=
γ
t
\frac{dK}{dt} = \gamma t
d
t
d
K
​
=
γ
t
, where
γ
\gamma
γ
is a positive constant of appropriate dimensions. Which of the following statements is (are) true?
[JEE Adv 2018 P2]
The force applied on the particle is constant
The speed of the particle is proportional to time
The distance of the particle from the origin increases linearly with time
The force is conservative
Validate
Solution:
d
k
d
t
=
γ
t
\frac{dk}{dt} = \gamma t
d
t
d
k
​
=
γ
t
as
k
=
1
2
m
v
2
∴
d
k
d
t
=
m
v
d
v
d
t
=
γ
t
∴
m
∫
0
v
v
 
d
v
=
γ
∫
0
t
t
 
d
t
  
  
  
  
m
v
2
2
=
γ
t
2
2
k = \frac{1}{2} m v^2 \therefore \frac{dk}{dt} = m v \frac{dv}{dt} = \gamma t \therefore m \int\limits_{0}^{v} v \, dv = \gamma \int\limits_{0}^{t} t \, dt \;\;\;\; \frac{m v^2}{2} = \frac{\gamma t^2}{2}
k
=
2
1
​
m
v
2
∴
d
t
d
k
​
=
m
v
d
t
d
v
​
=
γ
t
∴
m
0
∫
v
​
v
d
v
=
γ
0
∫
t
​
t
d
t
2
m
v
2
​
=
2
γ
t
2
​
v
=
γ
m
t
  
  
  
  
a
=
d
v
d
t
=
γ
m
=
v = \sqrt{\frac{\gamma}{m}} t \;\;\;\; a = \frac{dv}{dt} = \sqrt{\frac{\gamma}{m}} =
v
=
m
γ
​
​
t
a
=
d
t
d
v
​
=
m
γ
​
​
=
Constant  Since 
F
=
m
a
F = m a
F
=
ma
  
∴
F
=
m
γ
m
=
γ
m
=
\therefore F = m \sqrt{\frac{\gamma}{m}} = \sqrt{\gamma m} =
∴
F
=
m
m
γ
​
​
=
γm
​
=
Constant
© examsnet.com
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