A photoelectric material having work function ₀ is illuminated with light of wavelength λ≤ft(λ [JEE Adv 2017 P2]

Correct Answer is : λd3λ2λ_d³/λ²λ2λd3

Correct Answer is : λd3λ2λ_d³/λ²λ2λd3

Test Index

Dual Nature of Radiation

Section: Physics

Question : 9 of 24

Marks: +1, -0

\phi_0

\lambda\left(\lambda < \frac{hc}{\phi_0}\right)

\lambda_d

\Delta\lambda

\Delta\lambda_d

\lambda_d

\frac{\Delta\lambda_d}{\Delta\lambda}

Solution:

K=\frac{p^2}{2m}=\frac{h^2}{2m\lambda d^2}

\frac{hc}{\lambda}=\phi_0+\frac{h^2}{2m\lambda d^2}

\Rightarrow -\frac{hc}{\lambda^2} \frac{d\lambda}{d\lambda_d} = -\frac{h^{2}2}{2m\lambda_d^3} \Rightarrow \frac{\Delta\lambda_d}{\Delta\lambda} \propto \frac{\lambda_d^3}{\lambda^2}

Go to Question:

Prev Question

Next Question