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Electrostatics

Section: Physics

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Question : 19

Total: 59

A circular disc of radius R carries surface charge density σ(r)=σ0(1−

), where σ0 is a constantand r is the distance from the center of the disc. Electric flux through a large spherical surface thatencloses the charged disc completely is ϕ0. Electric flux through another spherical surface of radius

and concentric with the disc is ϕ. Then the ratio

[JEE Adv 2020 P1]

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