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Section:
Physics
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© examsnet.com
Question : 31 of 61
Marks:
+1
,
-0
Consider a uniform spherical charge distribution of radius
R
1
R_1
R
1
centred at the origin O.In this distribution,a spherical cavity of radius
R
2
R_2
R
2
,centred at P with distance
O
P
=
a
=
R
1
−
R
2
OP=a=R_1-R_2
OP
=
a
=
R
1
−
R
2
(see figure)
is made if the electric field inside the cavity at position
r
⃗
is
E
⃗
(
r
⃗
)
\vec{r}\;\text{is}\;\vec{E}(\vec{r})
r
is
E
(
r
)
,then the correct statement(s) is (are)
[JEE Adv 2015 P2]
E
⃗
\vec{E}
E
is uniform, its magnitude is independent of
R
2
R_2
R
2
but its direction depends on
r
⃗
\vec{r}
r
E
⃗
\vec{E}
E
is uniform, its magnitude depends of
R
2
R_2
R
2
and its direction depends on
r
⃗
\vec{r}
r
E
⃗
\vec{E}
E
is uniform, its magnitude is independent of
a
a
a
but its direction depends on
a
⃗
\vec{a}
a
E
⃗
\vec{E}
E
is uniform and both its magnitude and direction depends on
a
⃗
\vec{a}
a
Validate
Solution:
E
⃗
=
ρ
3
ε
0
C
1
C
2
⃗
\vec{E}=\frac{\rho}{3\varepsilon_0}\vec{C_1C_2}
E
=
3
ε
0
ρ
C
1
C
2
C
1
⇒
C_1\Rightarrow
C
1
⇒
center of sphere and
C
2
⇒
C_2\Rightarrow
C
2
⇒
center of cavity
© examsnet.com
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