Test Index

Electrostatics

Section: Physics

Question : 43 of 61

Marks: +1, -0

The net electric flux crossing the plane x = +a/2 is equal to the net electric flux crossing the plane x = –a/2.
The net electric flux crossing the plane y = +a/2 is more than the net electric flux crossing the plane y = –a/2.
The net electric flux crossing the entire region is $\frac{q}{\varepsilon_0}$ .
The net electric flux crossing the plane z = +a/2 is equal to the net electric flux crossing the plane z = –a/2.

Solution:

The net flux through the cubical region is given by

\frac{-q+3q-q}{\varepsilon_0}

\frac{q}{\varepsilon_0}

Due to symmetry, the flux passing through the faces

x =

\frac{-q}{2}

, x =

\frac{+a}{2}

, z =

\frac{+a}{2}

are same.

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