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Geometrical Optics
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Section:
Physics
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Question : 17 of 59
Marks:
+1
,
-0
For a prism of prism angle
θ
=
6
0
∘
θ=60^{\circ}
θ
=
6
0
∘
, the refractive indices of the left half and the right half are, respectively,
n
1
n_{1}
n
1
and
n
2
n_{2}
n
2
(
n
2
≥
n
1
n_{2} \geq n_{1}
n
2
≥
n
1
) as shown in the figure. The angle of incidence
i
i
i
is chosen such that the incident light rays will have minimum deviation if
n
1
=
n
2
=
n
=
1.5
n_{1}=n_{2}=n=1.5
n
1
=
n
2
=
n
=
1.5
. For the case of unequal refractive indices
n
1
=
n
n_{1}=n
n
1
=
n
and
n
2
=
n
+
Δ
n
n_{2}=n+\Delta n
n
2
=
n
+
Δ
n
(where
Δ
n
≪
n
\Delta n \ll n
Δ
n
≪
n
), the angle of emergence
e
=
i
+
Δ
e
e=i+\Delta e
e
=
i
+
Δ
e
. Which of the following statement(s) is (are) correct?
[JEE Adv 2021 P2]
The value of
Δ
e
\Delta e
Δ
e
(in radians) is greater than that of
Δ
n
\Delta n
Δ
n
Δ
e
\Delta e
Δ
e
is proportional to
Δ
n
\Delta n
Δ
n
Δ
e
\Delta e
Δ
e
lies between
2.0
2.0
2.0
and
3.0
3.0
3.0
milliradians, if
Δ
n
=
2.8
×
1
0
−
3
\Delta n = 2.8 \times 10^{-3}
Δ
n
=
2.8
×
1
0
−
3
Δ
e
\Delta e
Δ
e
lies between
1.0
1.0
1.0
and
1.6
1.6
1.6
milliradians, if
Δ
n
=
2.8
×
1
0
−
3
\Delta n = 2.8 \times 10^{-3}
Δ
n
=
2.8
×
1
0
−
3
Validate
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