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Magnetism

Section: Physics

Question : 34 of 48

Marks: +1, -0

\overset{\rightarrow}{u_1}= \hat{4i}\; \text{ms}^{-1},

\overset{\rightarrow}{u_2}= 2(\sqrt{3}\hat{i} \; + \hat{j}) \; \text{ms}^{-1}

The direction of the magnetic field is -z direction.
The direction of the magnetic field is +z direction
The magnitude of the magnetic fieId $\frac{50 \text{M} \pi}{3 \text{Q}}$ units
The magnitude of the magnetic field is $\frac{100 \pi \text{M}}{3 \text{Q}}$ units

Solution:

So magnetic field is along -ve, z-direction.

Time taken in the magnetic field =

10 \times 10^{-3} = \frac{\pi M}{6QB}

B= \frac{\pi M}{60 \times 10^{-3} Q} = \frac{1000 \pi M}{60 Q}

\frac{50 \pi M}{3 Q}

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