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JEE Main 08 Apr 2018 Code A Solved Paper
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© examsnet.com
Question : 47
Total: 90
The oxidation states of Cr in
[
C
r
(
H
2
O
)
6
]
C
l
3
,
[
C
r
(
C
6
H
6
)
2
]
, and
K
2
[
C
r
(
C
N
)
2
(
O
)
2
(
O
)
2
(
N
H
3
)
]
respectively are :
+
3
,
+
4
and
+
6
+
3
,
+
2
and
+
2
+
3
,
0
and
+
6
+
3
,
0
and
+
4
Validate
Solution:
[
C
r
(
H
2
O
)
6
]
C
l
3
x
+
0
−
3
=
0
x
=
+
3
(
C
r
C
C
6
H
6
)
2
x
+
0
=
0
x
=
0
k
2
[
G
(
C
N
)
2
(
O
)
2
(
O
)
2
(
N
H
3
)
]
+
2
+
x
−
2
−
4
+
0
+
0
=
0
x
=
+
4
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