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JEE Main 09 April 2016 Paper
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© examsnet.com
Question : 4
Total: 90
A car of weight W is on an inclined road that rises by 100 m over a distance of 1 km and applies a constant frictional force
W
20
on the car. While moving uphill on the road at a speed of
10
m
s
−
1
, the car needs power P. If it needs power
P
2
while moving downhill at speed
υ
then value of
υ
is :
20
m
s
−
1
15
m
s
−
1
10
m
s
−
1
5
m
s
−
1
Validate
Solution:
While going up
(
sin
θ
=
tan
θ
=
1
10
)
W
sin
θ
10
+
W
20
10
=
P
3
W
2
=
P
While going down
W
20
v
=
P
2
=
3
W
4
v
=
15
m/s
© examsnet.com
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